Comments on: AETHER: The Physicalists’ God http://cyberdyno.wordpress.com/2008/07/27/introduction/ How could God think or see with neither brains nor eyes? Mon, 26 Jan 2009 13:11:35 +0000 http://wordpress.com/ hourly 1 By: Laurent Duchesne http://cyberdyno.wordpress.com/2008/07/27/introduction/#comment-14 Laurent Duchesne Mon, 26 Jan 2009 13:11:35 +0000 http://cyberdyno.wordpress.com/?p=3#comment-14 Can these be accurately applied to a GPS system? That's the next question. Can these be accurately applied to a GPS system?

That’s the next question.

]]> By: Joe Nahhas http://cyberdyno.wordpress.com/2008/07/27/introduction/#comment-13 Joe Nahhas Mon, 26 Jan 2009 11:19:17 +0000 http://cyberdyno.wordpress.com/?p=3#comment-13 Kepler (demolish)Vs Einstein's space jail of time r -------------- Exp (i wt) -----------S= r Exp (ì wt) Nahhas' Equation Orbit location-----------Orbit light sensing -------------- Visual orbit location Particle/Newton ---------------- --Visual -------------------------- Wave/Quantum Quantum - Newton=visual effects=relativistic effects=space-time confusions S= visual distance; r = actual distance; v = speed and c = light speed S = r Exp (i wt) = r [cosine (wt) + î sine (wt)] P =d S/d t = v Exp (ì w t) + ì r w Exp (ì w t); v=d r/d t; v=w r = v (1+ ì) [Exp (ì wt)] = visual velocity E (definition) = m/2(m v + m' r) ²; E = mc²/2 If v = 0; m' r=mc E (visual) = mp²/2 = mv²/2(1+ì) ² Exp 2(ì w t) E (visual) = mv²/2(1 + 2ì -1) [cos2wt + ì sin2wt] E (visual) = ì (mv²) [1-2sin²wt + 2i [sin (wt)] [cosine (wt)] If wt = (2n+1) π/4 E (visual) = ì (mv²) [1-1 ± ỉ] = ± (mc²); v = c 2-Central force law Areal velocity is constant: r² (d θ/d t) =h Kepler's Law h = 2π a b/T; b=a√ (1-ε²); a = mean distance value; ε = eccentricity r² (d θ/d t) = h = S² (d w/d t) Replace r with S = r exp (ỉ wt); h = [r² Exp (2iwt)] (d w/d t) (d w/d t) = (h/r²) exp [-2(i wt)] d w/d t= (h/r²) [cosine 2(wt) - ỉ sine 2(wt)] = (h/r²) [1- 2sine² (wt) - ỉ sin 2(wt)] d w/d t = d w(x)/d t + d w(y)/d t; d w(x)/d t = (h/r²) [ 1- 2sine² (wt)] d w(x)/d t – (h/r²) = - 2(h/r²)sine²(wt) = - 2(h/r²)(v/c)² v/c=sine wt (h/ r²)(Perihelion/Periastron)= [2πa.a√ (1-ε²)]/Ta² (1-ε) ²= [2π√ (1-ε²)]/T (1-ε) ² Δ w/d t = (d w/d t – h/r²] = -4π {[√ (1-ε²)]/T (1-ε) ²} (v/c) ² radian per second Δ w/d t = (- 4π /T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² radians Δ w°/d t = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² degrees; Multiplication by 180/π Δ w°/d t = (-720x36526/T) {[√ (1-ε²)]/(1-ε)²} (v/c)² degrees/100 years Δ w”/d t = (-720x3600/T) {[√ (1-ε²)]/(1-ε) ²} (v/c) ² seconds of arc multiplication by 3600 Δ w/d t = (-720x36526x3600/T) {[√ (1-ε²]/(1-ε)²} (v/c)² seconds of arc per century The circumference of an ellipse: 2πa (1 - ε²/4 + 3/16(ε²)²- --.) ≈ 2πa (1-ε²/4); R =a (1-ε²/4) v=√ [G m M / (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system Application 3: Advance of Perihelion of mercury. G=6.673x10^-11; M=2x10^30kg; m=.32x10^24kg ε = 0.206; T=88days; c = 299792.458 km/sec; a = 58.2km/sec Calculations yields: v =48.14km/sec [√ (1- ε²)] (1-ε) ² = 1.552 Δ w”= (-720x36526x3600/88) x (1.552) (48.14/299792)²=43.0”/century Conclusions: E ≠ mc² (special-relativity) and the 43" seconds of arc of advance of perihelion of Planet mercury (general-relativity) is are caused by deformed space-time physicists "thought" and not deformed space (x, y, z). Anyone dare to prove me wrong? E=mc²/2 E (Energy by definition) = mv²/2 = mc²/2; if v = c m = mass; v= speed; c= light speed; w= angular velocity; t= time S = r Exp (ì w t) = r [cos (wt) + ì sin (wt)] Visual effects P = visual velocity = change of visual location P = d S/d t = v Exp (ì w t) + ì w r Exp (ì w t) = (v + ì w r) Exp (ì w t) = v (1 + ì) Exp (ì w t) = visual speed; v = w r E (visual energy= what you see in lab) = m p²/2; replace v by p in E = mv²/2 = m p²/2 = m v²/2 (1 + ì) ² Exp (2ì wt) = mv²/2 (2ì) [cosine (2wt) + ì sine (2wt)] =ì mv² [1 - 2 sine² (wt) + 2 ì sine (wt) cosine (wt)];v = speed; c = light speed wt = π/2 E (visual) = ìmv² (1 - 2 + 0) E (visual) = -ì mc² ≡ mc² (absolute value;-ì = negative complex unit) If v = c w t = π/4 E (visual) = imv² [1-1 +ỉ] =-mc²; v = c wt =-π/4+ỉln2/2; 2ỉ wt=-ỉπ/2 - ln2 Exp (2i wt) = Exp [-ỉπ/2] Exp [ln(1/2)]=[-ỉ (1/2)] E (visual) = imv² (-ỉ/2) =1/2mc² v = c Conclusion: E = mc² is the visual Illusion of E = mc²/2 joenahhas1958@yahoo.com. All rights reserved. PS: In case of E=mc² claims to be rest energy claims then E=1/2m (m v + m' r) ² = (1/2m) (m' r) ²; v = 0 E = (1/2m) (mc) ²; m' r =mc E=mc²/2 Kepler (demolish)Vs Einstein’s space jail of time
r ————– Exp (i wt) ———–S= r Exp (ì wt) Nahhas’ Equation
Orbit location———–Orbit light sensing ————– Visual orbit location
Particle/Newton —————- –Visual ————————– Wave/Quantum
Quantum – Newton=visual effects=relativistic effects=space-time confusions
S= visual distance; r = actual distance; v = speed and c = light speed
S = r Exp (i wt) = r [cosine (wt) + î sine (wt)]
P =d S/d t = v Exp (ì w t) + ì r w Exp (ì w t); v=d r/d t; v=w r
= v (1+ ì) [Exp (ì wt)] = visual velocity
E (definition) = m/2(m v + m’ r) ²; E = mc²/2 If v = 0; m’ r=mc
E (visual) = mp²/2 = mv²/2(1+ì) ² Exp 2(ì w t)
E (visual) = mv²/2(1 + 2ì -1) [cos2wt + ì sin2wt]
E (visual) = ì (mv²) [1-2sin²wt + 2i [sin (wt)] [cosine (wt)]
If wt = (2n+1) π/4
E (visual) = ì (mv²) [1-1 ± ỉ] = ± (mc²); v = c
2-Central force law Areal velocity is constant: r² (d θ/d t) =h Kepler’s Law
h = 2π a b/T; b=a√ (1-ε²); a = mean distance value; ε = eccentricity
r² (d θ/d t) = h = S² (d w/d t)
Replace r with S = r exp (ỉ wt); h = [r² Exp (2iwt)] (d w/d t)
(d w/d t) = (h/r²) exp [-2(i wt)]
d w/d t= (h/r²) [cosine 2(wt) - ỉ sine 2(wt)] = (h/r²) [1- 2sine² (wt) - ỉ sin 2(wt)]
d w/d t = d w(x)/d t + d w(y)/d t; d w(x)/d t = (h/r²) [ 1- 2sine² (wt)]
d w(x)/d t – (h/r²) = – 2(h/r²)sine²(wt) = – 2(h/r²)(v/c)² v/c=sine wt
(h/ r²)(Perihelion/Periastron)= [2πa.a√ (1-ε²)]/Ta² (1-ε) ²= [2π√ (1-ε²)]/T (1-ε) ²
Δ w/d t = (d w/d t – h/r²] = -4π {[√ (1-ε²)]/T (1-ε) ²} (v/c) ² radian per second
Δ w/d t = (- 4π /T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² radians
Δ w°/d t = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² degrees; Multiplication by 180/π
Δ w°/d t = (-720×36526/T) {[√ (1-ε²)]/(1-ε)²} (v/c)² degrees/100 years
Δ w”/d t = (-720×3600/T) {[√ (1-ε²)]/(1-ε) ²} (v/c) ² seconds of arc multiplication by 3600
Δ w/d t = (-720×36526x3600/T) {[√ (1-ε²]/(1-ε)²} (v/c)² seconds of arc per century
The circumference of an ellipse: 2πa (1 – ε²/4 + 3/16(ε²)²- –.) ≈ 2πa (1-ε²/4); R =a (1-ε²/4) v=√ [G m M / (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system
Application 3: Advance of Perihelion of mercury.
G=6.673×10^-11; M=2×10^30kg; m=.32×10^24kg
ε = 0.206; T=88days; c = 299792.458 km/sec; a = 58.2km/sec
Calculations yields:
v =48.14km/sec
[√ (1- ε²)] (1-ε) ² = 1.552
Δ w”= (-720×36526x3600/88) x (1.552) (48.14/299792)²=43.0”/century
Conclusions:
E ≠ mc² (special-relativity) and the 43" seconds of arc of advance of perihelion of Planet mercury (general-relativity) is are caused by deformed space-time physicists "thought" and not deformed space (x, y, z).

Anyone dare to prove me wrong?
E=mc²/2
E (Energy by definition) = mv²/2 = mc²/2; if v = c
m = mass; v= speed; c= light speed; w= angular velocity; t= time
S = r Exp (ì w t) = r [cos (wt) + ì sin (wt)] Visual effects
P = visual velocity = change of visual location
P = d S/d t = v Exp (ì w t) + ì w r Exp (ì w t)
= (v + ì w r) Exp (ì w t) = v (1 + ì) Exp (ì w t) = visual speed; v = w r
E (visual energy= what you see in lab) = m p²/2; replace v by p in E = mv²/2
= m p²/2 = m v²/2 (1 + ì) ² Exp (2ì wt)
= mv²/2 (2ì) [cosine (2wt) + ì sine (2wt)]
=ì mv² [1 - 2 sine² (wt) + 2 ì sine (wt) cosine (wt)];v = speed; c = light speed
wt = π/2
E (visual) = ìmv² (1 – 2 + 0)
E (visual) = -ì mc² ≡ mc² (absolute value;-ì = negative complex unit) If v = c
w t = π/4
E (visual) = imv² [1-1 +ỉ] =-mc²; v = c
wt =-π/4+ỉln2/2; 2ỉ wt=-ỉπ/2 – ln2
Exp (2i wt) = Exp [-ỉπ/2] Exp [ln(1/2)]=[-ỉ (1/2)]
E (visual) = imv² (-ỉ/2) =1/2mc² v = c
Conclusion: E = mc² is the visual Illusion of E = mc²/2 joenahhas1958@yahoo.com. All rights reserved.
PS: In case of E=mc² claims to be rest energy claims then
E=1/2m (m v + m’ r) ² = (1/2m) (m’ r) ²; v = 0
E = (1/2m) (mc) ²; m’ r =mc
E=mc²/2

]]> By: Laurent Duchesne http://cyberdyno.wordpress.com/2008/07/27/introduction/#comment-12 Laurent Duchesne Wed, 21 Jan 2009 17:58:06 +0000 http://cyberdyno.wordpress.com/?p=3#comment-12 GPS technology is possible because of Einstein's Relativity equations. Time flows faster at GPS satellite's altitude than it does on Earth's surface. Time and space are relative, it is a fact. GPS technology is possible because of Einstein’s Relativity equations.

Time flows faster at GPS satellite’s altitude than it does on Earth’s surface. Time and space are relative, it is a fact.

]]> By: Joe Nahhas http://cyberdyno.wordpress.com/2008/07/27/introduction/#comment-11 Joe Nahhas Wed, 21 Jan 2009 15:32:08 +0000 http://cyberdyno.wordpress.com/?p=3#comment-11 20th century Aether is Einstein's space-time that led to fraud symbol E=mc2 without a proof and came out By replacing "Science" with White Trash known as "Thought" experiments and cost cutter "junk" experimentations. The experimental proofs amounts to nothing because they all can be expalined as measurement errors and I can prove that. Just ask for a proof. For four hundred years physicists and Astro-physcists and mathematicians missed Kepler's time dependent equation that expalins all of "relativistic" efects as measurements errors 20th century Aether is Einstein’s space-time that led to fraud symbol E=mc2 without a proof and came out By replacing “Science” with White Trash known as “Thought” experiments and cost cutter “junk” experimentations. The experimental proofs amounts to nothing because they all can be expalined as measurement errors and I can prove that.
Just ask for a proof.
For four hundred years physicists and Astro-physcists and mathematicians missed Kepler’s time dependent equation that expalins all of “relativistic” efects as measurements errors

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